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Find the intervals in which the following functions are strictly increasing or decreasing:
x2+ 2x – 5


Let straight f left parenthesis straight x right parenthesis space equals space straight x squared plus 2 straight x minus 5 space space space space space space space space space space space therefore space space space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space 2 straight x plus 2
Now,   straight f apostrophe left parenthesis straight x right parenthesis greater than 0 space space when space 2 straight x plus 2 greater than 0 space space space straight i. straight e. space space space when space straight x greater than negative 1
therefore space space space space straight f left parenthesis straight x right parenthesis space is space increasing space in space left parenthesis negative 1 comma space infinity right parenthesis.
Also,  straight f apostrophe left parenthesis straight x right parenthesis less than 0 space when space 2 straight x plus 2 less than 0 space space space space straight i. straight e. space when space straight x space less than space minus space 1
therefore space space space space straight f left parenthesis straight x right parenthesis space is space decreasing space in space left parenthesis negative infinity comma space minus 1 right parenthesis.

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Find the intervals in which the following functions are strictly increasing or decreasing:
10 – 6x – 2x2


Let  straight f left parenthesis straight x right parenthesis space equals space 10 minus 6 straight x minus 2 straight x squared space                             therefore space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus 6 minus 4 straight x
Now,  straight f apostrophe left parenthesis straight x right parenthesis greater than 0 space space space space space when space space space minus 6 minus 4 straight x space greater than 0 space space space space space straight i. straight e. space when space straight x space less than negative 3 over 2.
therefore space space space space space straight f left parenthesis straight x right parenthesis space is space increasing space in space open parentheses negative infinity comma space minus 3 over 2 close parentheses.
  Also space straight f apostrophe left parenthesis straight x right parenthesis space less than space 0 space space space when space minus 6 minus 4 straight x space less than 0 space space space straight i. straight e. space when space straight x space greater than space minus 3 over 2.
therefore space space space space straight f left parenthesis straight x right parenthesis space is space decreasing space in space open parentheses negative 3 over 2 comma space infinity close parentheses.

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Which of the following function are strictly decreasing on open parentheses 0 comma space straight pi over 2 close parentheses space ?
(a) cos x   (b) cos 2x   (c) cos 3x   (d) tan x

(a) Let straight f left parenthesis straight x right parenthesis space equals space cos space straight x comma space space space space space space space space therefore space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus sin space straight x space
In open parentheses 0 comma space straight pi over 2 close parentheses comma space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus sin space straight x space less than space 0
 therefore space space space space straight f left parenthesis straight x right parenthesis space equals space cosx space is space strictly space decreasing space on space open parentheses 0 comma space straight pi over 2 close parentheses

(b) Let straight f left parenthesis straight x right parenthesis space equals space cos space 2 straight x comma space space space space space space therefore space space space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus 2 space sin space 2 straight x
In open parentheses 0 comma space straight pi over 2 close parentheses comma space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus 2 space sin space 2 straight x space less than space 0
therefore space space space space space straight f left parenthesis straight x right parenthesis space equals space cos space 2 straight x is strictly decreasing on open parentheses 0 comma space straight pi over 2 close parentheses.
(c)  Let f(x) = cos 3x,       therefore space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus 3 space sin space 3 straight x
                           0 less than straight x less than straight pi over 2
rightwards double arrow space space space space space space 0 less than space 3 straight x space less than space fraction numerator 3 straight pi over denominator 2 end fraction
Now  straight f apostrophe left parenthesis straight x right parenthesis space less than 0 space space space space when space 0 space less than space 3 straight x space less than space straight pi
and straight f apostrophe left parenthesis straight x right parenthesis space greater than 0 space space space when space straight pi space less than space 3 straight x space less than fraction numerator 3 straight pi over denominator 2 end fraction
therefore space space space space space straight f left parenthesis straight x right parenthesis space is space not space straight a space strictly space decreasing space function space on space open parentheses 0 comma space space straight pi over 2 close parentheses

(d) Let straight f left parenthesis straight x right parenthesis space equals tanx comma space space space space space space space space therefore space space space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space sec squared straight x
Now,    straight f apostrophe left parenthesis straight x right parenthesis greater than 0 space space for all space straight x space space space space element of space space space open parentheses 0 comma space space straight pi over 2 close parentheses
therefore space space space straight f left parenthesis straight x right parenthesis space is space not space straight a space strictly space decreasing space function space on space open parentheses 0 comma space space space straight pi over 2 close parentheses

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Find the intervals in which the following functions are strictly increasing or decreasing:
6 – 9x – x 2


Let f(x) = 6 – 9x – x 2                               therefore space space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus 9 minus 2 straight x
Now,     straight f apostrophe left parenthesis straight x right parenthesis greater than 0 space space space when space minus 2 straight x minus 9 greater than 0 space space straight i. straight e. space space space when space straight x space less than negative 9 over 2
therefore space space space straight f left parenthesis straight x right parenthesis space is space increasing space for space straight x less than negative 9 over 2
therefore space space space space straight f left parenthesis straight x right parenthesis space is space increasing space in space open parentheses negative infinity comma space space fraction numerator negative 9 over denominator 2 end fraction close parentheses.
Also comma space straight f apostrophe left parenthesis straight x right parenthesis space less than space 0 space space when space minus 2 straight x minus 9 less than 0 space space space straight i. straight e. space when space straight x greater than negative 9 over 2
therefore space space space space straight f left parenthesis straight x right parenthesis space is space increasing space for space straight x space greater than negative 9 over 2
therefore space space space space space space straight f left parenthesis straight x right parenthesis space is space decreasing space in space open parentheses negative 9 over 2 comma space space infinity close parentheses.

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Prove that the function f(x) = x3 – 3x2 + 3x – 100 is increasing on R.


Here f(x) = x3 – 3x2 + 3x – 100
Df = R
f ' (x) = 3x2 – 6 x + 3 = 3 (x2 – 2 x + 1) = 3 (x – 1)2 ≥ 0 ∀ x ∊ R
∴   f (x) is increasing on R.

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